// For a balanced substring with one char, any length works (all chars are equal) maxlen = Math.max(maxlen, getLength(s, 'a')); // Consider 'b' and 'c' maxlen = Math ...
// 利用helper method，以当前位置i（奇数palindrome）或i和i+1（偶数palindrome）为中心，向两边扩散寻找局部最长palindrome。 // 解法二 ...
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